Stop and uninstall an application using wsadmin

Before the application can be unsinstalled it must be stopped.
Steps:

1. Open wsadmin (with jython)
1.1 Go to "WebSphere_Profile_Root"/bin
1.2 Execute

wsadmin.sh(.bat) -lang jython

1.3 Enter UserID/Password (if promted)

2. Define needed cell and node variables
2. Execute

cell=AdminConfig.list('Cell')
cellname=AdminConfig.showAttribute(cell,'name')
nodes=AdminConfig.list('Node',cell)
nodename=AdminConfig.showAttribute(nodes,'name')
-----------------------------------
(Alternative:
e.g.: nodename=NAME_OF_NODE)

3. Define application manager variable

3.1 Execut

appManager=AdminControl.queryNames
('type=ApplicationManager,cell='+cellname+',
node='+nodename+',process=<APP_SERVER_NAME>,*')

3.2 To print out variable execute

print appManager

4. Assign application to variable
4.1 Execute

app=AdminControl.queryNames
('type=Application,cell='+cellname+',node='+nodename+',
process=<APP_SERVER_NAME>,J2EEName=<NAME_OF_APPLICATION>,*')

4.2 To print out variable execute

print app

5. Define application name to variable
5.1 Execute

appName=AdminControl.getAttributes(app,'name')

5.2 To print out variable execute

print appName

6. Stop application
6.1 Execute

AdminControl.invoke(appManager,'stopApplication', appName)

7. Uninstall application
7.1 Execute

AdminApp.uninstall(appName)

8. Save changes
8.1 Execute
AdminConfig.save()


Hint:
It is easier to use administrative console :-)
<APP_SERVER_NAME> = Name of server (JVM) where the application is deployed
<NAME_OF_APPLICATION> = Name of the application (not the ear-files name)